SAT Topic 2

Percentages

Percent of a number, percent change, increase/decrease, recovering originals.

Concept

Three ideas you'll use over and over:

Successive percent changes don't add. A 10% increase followed by a 10% decrease gives 1.10 × 0.90 = 0.99 — a net 1% decrease. This is a classic SAT trap.

To recover the original after a percent change: divide by the multiplier. e.g. after a 25% discount, the sale price is 0.75 × original, so original = sale / 0.75.

Worked example 1

After a 30% discount, a jacket costs $42. What was the original price?

Solution
Multiplier. 30% off ⇒ pay 70% of original: 0.70 · original = 42
Solve. original = 42 / 0.70 = 60
Original price $60.

Worked example 2

A product's price went from $50 to $65. Find the percent change.

Solution
Difference. 65 − 50 = 15
Divide by old. 15 / 50 = 0.30
30% increase.

Practice test

8 questions on percent of a number, percent change, increases/decreases, and recovering originals.

Practice test · 8 questions Question 1 of 8 · Score 0