Percent of a number, percent change, increase/decrease, recovering originals.
Three ideas you'll use over and over:
(p/100) · N.(new − old) / old × 100%.Successive percent changes don't add. A 10% increase followed by a 10% decrease gives 1.10 × 0.90 = 0.99 — a net 1% decrease. This is a classic SAT trap.
To recover the original after a percent change: divide by the multiplier. e.g. after a 25% discount, the sale price is 0.75 × original, so original = sale / 0.75.
0.70 · original = 42original = 42 / 0.70 = 6065 − 50 = 1515 / 50 = 0.308 questions on percent of a number, percent change, increases/decreases, and recovering originals.